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# 2 q's- please help, ty!

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2 q's- please help, ty! Apr 26, 2018

### Best Answer

#1
+3

Question 1: Simplify the expression: \((2-3i)(4+2i)\)

For this, we'll use the FOIL method.

2*4=8

8+__+__+__

2*2i=4i

8+4i+__+__

-3i*4=-12i

8+4i-12i+__

-3i*2i=-6i2

(I'm assuming i=sqrt(-1))

8+4i-12i+6=14-8i

Option S is your answer

Question 2: Simplify the expression: \((3x^4+9x^3-7x+15)+(-6x^4-8x^2+5x-3)\)

This is adding like terms.

First, let's start with x^4

3-6=-3

-3x4+9x3-8x2+__+__

There were only one x^3 and x^2 in the expression, so we know that part for sure.

Now, to the x term.

-7+5=-2

-3x4+9x3-8x2-2x+__

Now, to the normal numbers.

15-3=12

Final answer: -3x4+9x3-8x2-2x+12

Hope this helped!

Apr 26, 2018
edited by rarinstraw1195  Apr 26, 2018

### 4+0 Answers

#1
+3
Best Answer

Question 1: Simplify the expression: \((2-3i)(4+2i)\)

For this, we'll use the FOIL method.

2*4=8

8+__+__+__

2*2i=4i

8+4i+__+__

-3i*4=-12i

8+4i-12i+__

-3i*2i=-6i2

(I'm assuming i=sqrt(-1))

8+4i-12i+6=14-8i

Option S is your answer

Question 2: Simplify the expression: \((3x^4+9x^3-7x+15)+(-6x^4-8x^2+5x-3)\)

This is adding like terms.

First, let's start with x^4

3-6=-3

-3x4+9x3-8x2+__+__

There were only one x^3 and x^2 in the expression, so we know that part for sure.

Now, to the x term.

-7+5=-2

-3x4+9x3-8x2-2x+__

Now, to the normal numbers.

15-3=12

Final answer: -3x4+9x3-8x2-2x+12

Hope this helped!

rarinstraw1195 Apr 26, 2018
edited by rarinstraw1195  Apr 26, 2018
#2
+2

EDIT: Included Question 2

rarinstraw1195  Apr 26, 2018
#3
+1

Thanks, Rarinstraw  !!!   CPhill  Apr 26, 2018
#4
+2

Tysm! :D

RainbowPanda  Apr 26, 2018