+0

0
1392
4
+2448

Apr 26, 2018

#1
+5265
+3

Question 1: Simplify the expression: \((2-3i)(4+2i)\)

For this, we'll use the FOIL method.

2*4=8

8+__+__+__

2*2i=4i

8+4i+__+__

-3i*4=-12i

8+4i-12i+__

-3i*2i=-6i2

(I'm assuming i=sqrt(-1))

8+4i-12i+6=14-8i

Question 2: Simplify the expression: \((3x^4+9x^3-7x+15)+(-6x^4-8x^2+5x-3)\)

3-6=-3

-3x4+9x3-8x2+__+__

There were only one x^3 and x^2 in the expression, so we know that part for sure.

Now, to the x term.

-7+5=-2

-3x4+9x3-8x2-2x+__

Now, to the normal numbers.

15-3=12

Hope this helped!

Apr 26, 2018
edited by rarinstraw1195  Apr 26, 2018

#1
+5265
+3

Question 1: Simplify the expression: \((2-3i)(4+2i)\)

For this, we'll use the FOIL method.

2*4=8

8+__+__+__

2*2i=4i

8+4i+__+__

-3i*4=-12i

8+4i-12i+__

-3i*2i=-6i2

(I'm assuming i=sqrt(-1))

8+4i-12i+6=14-8i

Question 2: Simplify the expression: \((3x^4+9x^3-7x+15)+(-6x^4-8x^2+5x-3)\)

3-6=-3

-3x4+9x3-8x2+__+__

There were only one x^3 and x^2 in the expression, so we know that part for sure.

Now, to the x term.

-7+5=-2

-3x4+9x3-8x2-2x+__

Now, to the normal numbers.

15-3=12

Hope this helped!

rarinstraw1195 Apr 26, 2018
edited by rarinstraw1195  Apr 26, 2018
#2
+5265
+2

EDIT: Included Question 2

rarinstraw1195  Apr 26, 2018
#3
+129209
+1

Thanks, Rarinstraw  !!!

CPhill  Apr 26, 2018
#4
+2448
+2

Tysm! :D

RainbowPanda  Apr 26, 2018