2 q's- please help, ty!

Question 1: Simplify the expression: $(2-3i)(4+2i)$

For this, we'll use the FOIL method.

2*4=8

8+__+__+__

2*2i=4i

8+4i+__+__

-3i*4=-12i

8+4i-12i+__

-3i*2i=-6i²

(I'm assuming i=sqrt(-1))

8+4i-12i+6=14-8i

Option S is your answer

Question 2: Simplify the expression: $(3x^4+9x^3-7x+15)+(-6x^4-8x^2+5x-3)$

This is adding like terms.

First, let's start with x^4

3-6=-3

-3x⁴+9x³-8x²+__+__

There were only one x^3 and x^2 in the expression, so we know that part for sure.

Now, to the x term.

-7+5=-2

-3x⁴+9x³-8x²-2x+__

Now, to the normal numbers.

15-3=12

Final answer: -3x⁴+9x³-8x²-2x+12

Hope this helped!