Soyoxxommm

Let s denotes screws and n denotes nails.

Initially, there was a total of 145 screws and

nails implies s + n = 145 (1)

Total number of nails and screws used for

wooden cupboard = 4/7s + 3/5n

After constructing wooden cupboard, equal number

of screws and nails and left,

=> S - 4/7s = n - 3/5n.

=> 7S-4S/7 = 5n-3n/5

=> 7S-4S/7 = 5n-3/5

=> 3S * 5 = 2n * 7

=> 15s - 14n = 0 (2)

(1) * 15 => 15s+15n=2175 (3)

(3) -(2) => 15n-(-14n)=2175-0

            => 29n=2175

            => n = 2175/29 = 75

Thus, number of nails used to construct

Wooden cupboard = 3/5 * 75

                              = 45

Let the cost of one ruler be:  x

Therefore cost of 1 magnet is: 3x
 

Let his saving be: S

Now:

7x+12(3x)=S/3

7x+36x=S/3

43x=S/3

x=S/129

S=129x

Now we have to find the number of rulers purchased by him in 2S/9

2/9S=2/9*129x

2/9S≈$28.67x

Hence John bought 28  rulers.
 

C = No. of curry puffs = 256 + 5

S = No. of sardines puffs = S

We have,  C - S = 256 ---- (1)

           (C - C/4) + (S - 25/3) = total available stock 

                C/4 + 25/3 = total sold-out stock 

 Total sold eat = 377 - 256 = 121
 

∴     C/4 + 25/3 = 121 --- (2)

∴  Solving (1) and (2)

    C = 256 + S put in (2)

         \( {256 + S \over 4} + {25 \over 3} = 121\)
         S = 62.181 ~ 63

 ∴      C = 319.

(a) Total curry puffs = 319.

(b) Profits by selling S = 63/3 * 2 = 42.

    ∴        42 * 1.3$ = 54.6$

Step 1-  Given Informations : -

Danny has 2/3 as many toy cars as Jack. They have a total of 75 toy cars. How many toy cars does Jack have at first? How many toy cars must Jack give to Danny so that Danny will have 35 more toy cars than Jack?

According to Given Problem : -

               Danny has 2/3 as many toy cars as Jack.

                  total toy cars = 75

                     2/3J + J = 75 (According to Question)

                          5J/3 = 75

                            J \(= {75 * 3\over 5}\)

                            J = 45 

So, (Jack have = 45 toy cars at first)

 So, Danny have = 2/3 * J

                            = 2/3 * 45

                            = 30

       (Danny have = 30 toy cars at First)

Step 2- Now,

        We have to Find out how many cars (toy)

              must Jack Give to Danny so that Danny

        will have 35 more toy cars than Jack?

  Jack will Give (45-x) (∴x = Number of toy cars )

                                            Jack Give to Danny

 Now, Danny will have (30+x)

 So, According to Guide Situation : -

                      (45-x) + 35 = 30 + x

                         -x - x = 30 x 35 - 45

                         -2x = 30 - 80

                        -2x = -50

                           x = 25

(25 toy cars must Jack give to Danny, so 

       that Danny will have 35 more toy cars

           than Jack)

Let total no. of balls be x

==> (3/10)*x = 36

==> x = 120

No. of black balls = x-(3/8x+3/10x) = 13x/40 = (13/40)*120 = 39 balls

Ratio of marbles of Peter by Sam, P : S = 9 : 5

Now,  J : P : S = 36 : 63 : 35

(a)    Ratio of John by Sam : J : S = 36 : 35

(b)    Let the number of marbles with John = 36x

                                                           Peter = 63x

                                                           Sam = 35x

        When John Gabe 1/12 of his marble to Sam and

        Peter gave 1/9 of his marbles to Sam. Then

        
        marbles with Sam = 35x + (36x * 1/12)

                                                + (63 * 1/9)

                                      = 35x + 3x + 7x

                                      = 45x

        According to Question

           45x = 135

          => x = 135/45 = 3

  
      Total marbles + (36x + 63x + 35x) = 134x = 134 * 3

                                                                         = 402

Let total money Joe have = $x

Let Cost of can of drink = $y

     Hence cost of plate of chicken = $(y+3)

He spent 3/5 of his money on a can of drink and

 plate of chicken

Now money left = x - 3/5x = 2/5x

He spent rest of money to buy another 2 similar

cans of drink and has $1 left.

So Cost of 2 cans = y + y = $2y

Now money left = $1

     =>  2/5x - 2y = 1

     =>  2x - 10y = 5                 -- (A)

Also Cost of one can and a plate of chicken = 3/5x

            =>       y + (y + 3) = 3/5x

            =>     5 (2y + 3) = 3x

            =>       3x - 10y = 15                -- (B)

     Subtract (A) from (B) we get

                x = 10

      from (A)       y = 1/10 (2x-5) = 1/10 (20-5) = 1.5

  => Cost of Can of drink = $y = $1.5

this is required solution , may this help you.

let x represents the dollars owned by Tom

and y represents the dollars owned by Peter.

Given that, the price of the game cartridge is 

$45.

 If Tom buys the game cartridge, then the

money left to Tom is x−45. and the ratio of

his money and the Peter's is 1:3.

That is, \( {x-45 \over y}={1 \over 3}.\)
\( {x-45 \over y}={1 \over 3}.\) 
3x-135=y

3x-y=135

If Peter buys the game cartridge, then the

money left to Peter is y - 45. and the ratio of

his money and the Peter's is 3:5.

\( {y-45\over x}={3 \over 5}\)

3x=5y-225

x=5/3y-223/3

Substitute (2) in (1),
3x-y=135

3(5/3y-223/5)-y=135

y=90

Substitute y=90 in (2),

x=5/3(90)-225/3

x=75

Therefore, Tom has $75 and Peter has $90 at first.

Let total number of marbles in the bag were = x

Given, then jerry has marbles = 1/4 of the total number of marbles

                                         
                                                 = 1/4^x = x/4

       
          Lucas had marbles = x/4 + 36 = (36 more than Jerry)

          Kumar had marbles = 1/2 of the number of marbles

                                                was had

                                           = 1/2 (x/4 + 36)

          As, there were total x marbles in the bag

           So;

                    x = x/4 + (x/4 + 36) + 1/2(x/4 + 36)

                     
                       = 2x/4 + x/8 + 36 + 18

                    x = \( {4x+x \over 8}\) + 36 + 18

                   ^x- 5x/8 + 54

                      3x/8 = 54

                           x = \( {54 * 8 \over 3} = {432 \over 3} = 144\)

x = 144

a) 

   Lucas had marbles = (x/4 + 36)

                                   = 144/4 + 36

                                     = 36 + 36

                                      = 72

      So;     Lucas had 1/2 of the total marbles.

    b)     Total marbles were x = 144.

Zachary kept 290 balls in two boxes.

A as B

Let A ---> x balls => x+y=290 

      B ---> y

Now, 2/5A ---> B        B has total

                                     =y+2x/5

A has        x-2x/5=3x/5

Still A has 10 balls more than box B

        3x/5 = y+2x/5+10

   => 3x/5 - 2x/5 = y+10

   =>    x/5 = y+10

   =>    x - 5y = 50

   x+y=290

   x-5y=50

-   +      -

---------------                   |

      6y=240                   |    x = 290 - 40

        y=240/6=40          |        = 250

                                     |

There were 250 balls in A 

                     40 balls in B at first

THANKS! ;D

1 - 1/3 = 2/3

2/3x = 8

x = 12

He cut 12 pieces.

Set there are x levels.

   So 1/3x = 10      [ multiplication operation ]

       get x = 30

 So there are 30 levels Space Pals have.

https://web2.0calc.com/questions/using-equations

12.4