Joe spent 3/5 of his money on a can of drink and a plate of chicken rice. The plate of chicken rice cost $3 more than the can of drink. Joe then spent the rest of his money to buy another 2 similar cans of drink and had $1 left, find the cost of the can of drink.

Guest Aug 20, 2021

#1**+1 **

Let total money Joe have = $x

Let Cost of can of drink = $y

Hence cost of plate of chicken = $(y+3)

He spent 3/5 of his money on a can of drink and

plate of chicken

Now money left = x - 3/5x = 2/5x

He spent rest of money to buy another 2 similar

cans of drink and has $1 left.

So Cost of 2 cans = y + y = $2y

Now money left = $1

=> 2/5x - 2y = 1

=> 2x - 10y = 5 -- (A)

Also Cost of one can and a plate of chicken = 3/5x

=> y + (y + 3) = 3/5x

=> 5 (2y + 3) = 3x

=> 3x - 10y = 15 -- (B)

Subtract (A) from (B) we get

x = 10

from (A) y = 1/10 (2x-5) = 1/10 (20-5) = 1.5

=> Cost of Can of drink = $y = $1.5

this is required solution , may this help you.

Soyoxxommm Nov 6, 2021