fractions

Suppose Rocky has X no. of cookies

Then cookies left after Friday 

X- {(x/8)+14}

Cookies left after Saturday

[X-{(x/8) +14}] -[(3/10)(X-{(x/8)+14})+24]

Cookies left after Sunday

=[X-{(x/8) +14] - [(3/10)(X-{(x/8)+14})+24] -40....(1)

Since cookies left =34

Therefore equating the equation (1) with 34

(7/10){(7x/8) -14} -64 = 34

X=176

Thus Rocky has initially 176 cookies

$k - \left(\frac{1}{8} k + 14 + \frac{3}{10} \left(\frac{7}{8} k - 14 \right) + 24 + 40 \right)= 34$

$k - \frac{31k}{80} + \frac{21}{5} - 78 = 34$

$80k - 31k + 336 - 6240 = 2720$

$49k = 8624$

$k = \boxed{176}$

Ricky has some cookies. He ate 1/8 of his cookies and an additional 14 cookies on Friday. He then ate 3/10 of the remaining cookies and an additional 24 cookies on Saturday. He ate 40 cookies on Sunday and had 34 cookies left. How many cookies did Ricky have at first?

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

     x - [(1/8x + 14) + 3/10(x - 1/8x - 14) + 24 + 40] = 34

 Total  I     Friday   I        Saturday                 I Sun  I  left

x = 176