Straight

You know the sum beetween 1 and 9 is 45, multiply this by 10 (because there are 11 and 19, 21 and 29, ... 91 and 99) and that equals 450. The first digit could be all digits (except 0) and the second digit too, but it could be 0, but x + 0 = is still x. So we double the 450 and that is (450 * 2 =) 900 and now + 1 because of 100 (1 + 0 + 0 = 1). So (900 + 1 =) 901 is the solution.

Straight

Hello Guest,

from the sum beetween 1 and 9 is ($1+9*(\frac{9}{2})=$) 45, the sum beetween 10 and 19 is (45+10 =) 55, the sum beetween 20 and 29 is (45+20 =) 65, do this trick every time and you'll get the answer. May you response and tell me the answer?

Straight

Hello Guest,

как называется число с 83 нулями после числа

what is the number with 83 zeros after the number,

the number called 100 Tredecillion. (in German 100 Tredezilliarde and in Russian 100 тридециллионов.) I translated it with DeepL.

Straight

Russian:

Здравствуйте, гость,

число называется 100 Тредециллионов. (на немецком 100 Tredezilliarde и на русском 100 тридециллионов.) Я перевел его с помощью DeepL.

Straight

Hello Guest,

why you had multiply 11424 by 8/7? I thought you would do it with 7/8.

Straight

Hello sherwyo,

how about saying Thanks to him?

I think that's not polite to each other.

Straight

Hello,

($x,y=0,\frac{7}{5}$), the steps I will show soon.

Straight

Hello Guest,

the equation is not hard, but still I can say the answer: $16$. Now you can think how did I get to this answer and don't use the calculator, please.

When you know the answer, that's great.

Straight

Hello OdrogMath,

what about help anyone before asking questions?

Straight

Hello Guest,

$\frac{m}{m^2+5m-6}+\frac{2}{m+6}=\frac{1}{m-1}$ ,

$\frac{m}{m^2+5m-6}+\frac{2}{m+6}-\frac{1}{m-1}=0$ ,

$\frac{m}{m^2+6m-m-6}+\frac{2}{m+6}-\frac{1}{m-1}=0$ ,

$\frac{m}{m*(m+6)-m-6}+\frac{2}{m+6}-\frac{1}{m-1}=0$ ,

$\frac{m}{m*(m+6)-(m+6)}+\frac{2}{m+6}-\frac{1}{m-1}=0$ ,

$\frac{m}{(m+6)*(m-1)}+\frac{2}{m+6}-\frac{1}{m-1}=0$ ,

$\frac{m+2(m-1)-(m+6)}{(m+6)*(m-1)}=0$ ,

$\frac{m+2(m-1)-m-6}{(m+6)*(m-1)}=0$ ,

$\frac{2(m-1)-6}{(m+6)*(m-1)}=0$ ,

$\frac{2m-2-6}{(m+6)*(m-1)}=0$ ,

$\frac{2m-8}{(m+6)*(m-1)}=0$ ,

$2m-8=0$ ,

$2m=8$ ,

$m=4$ ,

so the solution is $m=4$ .

Straight