Hello Guest,
there's definitely any zeros because you're multiplying with 10. Just type in the calculator and get the solution (42744736671436800000). You see at the end there are 5 zeros and and nowhere else. Hope this was helpful.
Straight
\(\frac{4}{5}*\frac{4}{5}=\frac{4*4}{5*5}=\frac{16}{25}\),
\(\mbox {or }(\frac{4}{5})^2\), easy!
x = 27,
56 * ((27 * 3) + 8) = 4984,
56 * (81 + 8) = 4984,
56 * 89 = 4984,
4984 = 4984
true
that's the joke, there is no picture.
the solution is:
\(8+7+6+5+4+3+2+1=(8+1)*(8:2)=36 \mbox { possibilities}\) and that's also by three-, four-, five-, six-,...- digit numbers.
From reading through the question it looks difficult but has a simple solution.
like 1234567890. For the first digit there are 10 possibilities, for the second digit only 9 possibilities, for the third digit 8 possibilities,... and that makes 10! if you multiply all of them. There are only 2 possibilities that it is odd and even or even and odd, so \(\frac{10!}{2}=1814400 \mbox{ possibilities}\) .
maybe you just want the answer:
\(2x*(x-6)+x*(x-6)+9(x-6)\) ,
\(2x^2-12x+x*(x-6)+9(x-6)\) ,
\(2x^2-12x+x^2-6x+9(x-6)\) ,
\(2x^2-12x+x^2-6x+9x-54\) ,
\(3x^2-12x-6x+9x-54\) ,
\(3x^2-9x-54\) ,
so the solution is \(3x^2-9x-54\) .
I'm not sure, but still giving a try:
He can choose (0,0), (0,1) or (1,1), so the probability is 2/3.
I do not understand your problem. May that's because of your English, keep learning English, Guest. Describe your problem.
Compound time, what's this?
