How many 10-digit numbers are there, where the sum of the digits is divisible by 8?
Hello Guest,
the solution is:
\(8+7+6+5+4+3+2+1=(8+1)*(8:2)=36 \mbox { possibilities}\) and that's also by three-, four-, five-, six-,...- digit numbers.
From reading through the question it looks difficult but has a simple solution.
Straight
