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How many 10-digit numbers are there, where the sum of the digits is divisible by 8?

 Oct 4, 2021
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Hello Guest,

 

the solution is:

 

\(8+7+6+5+4+3+2+1=(8+1)*(8:2)=36 \mbox { possibilities}\) and that's also by three-, four-, five-, six-,...- digit numbers.

From reading through the question it looks difficult but has a simple solution.

 

Straight

 Oct 24, 2021

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