ok...
so TE = 116 + (58*9.81*6) = 5921.8
my gpe under 6M: .(58*9.81*6)= 3529.88
5805.8 - 3529.88 = 2275.92
2507.2 = 1/2 58v^2
86.48= v^2
v= 9.3 ms^-1
Thank you very much
thank you
question B is similar to a so i figured id just try it myself
try subbing it in formula b^2-4ac < 0 ( this represents when a quadratic formula has no real solution)
then rearrange it
thank you!
1. find gradient 2--6/7-3 = 8/4 = 2
m*m = -1
m= -0.5
sub the information u know into formula
y = mx + c or y - y1 = m(x -x1)
y = -0.5x + 0.5
ok thank you so much for helping!
ah ok thank you
one more question: does this method apply to all polar graphs such as when you have to solve tan and sin or is there a different method to do so
can you please explain how you find out -pi/3 = 5pi/3