ok...

so TE = 116 + (58*9.81*6) = 5921.8

my gpe under 6M: .(58*9.81*6)= 3529.88

5805.8 - 3529.88 = 2275.92

2507.2 = 1/2 58v^2

86.48= v^2

v= 9.3 ms^-1

Thank you very much

thank you

question B is similar to a so i figured id just try it myself

try subbing it in formula b^2-4ac < 0 ( this represents when a quadratic formula has no real solution)

then rearrange it

thank you!

1. find gradient 2--6/7-3 = 8/4 = 2

m*m = -1

m= -0.5

sub the information u know into formula

y = mx + c or y - y1 = m(x -x1)

y = -0.5x + 0.5

ok thank you so much for helping!

ah ok thank you

one more question: does this method apply to all polar graphs such as when you have to solve tan and sin or is there a different method to do so

can you please explain how you find out -pi/3 = 5pi/3