+845 
For this question I have used the kinetic equation to work out 1/2*58*4=116
please show me how to do B, thanks
+33661 Total energy (TE) = Kinetic energy (KE) + Potential energy (PE)
KE = (1/2).m.v2, where m is mass and v is velocity
PE = m.g.h, where g is gravitational acceleration and h is height (above pool surface).
Calculate TE at diving platform (you have already calculated the KE there).
Work out the PE at the point 6metres below the platform.
Then, because TE is conserved, you can set (1/2)mv2 + PEat6metresbelowplatform= TE, where v is now the velocity at 6m below the platform. This v is the only unknown, so you can rearrange the equation to find it.
Incidentally, you should really give your results with units: Joules for energy, metres/sec for velocity.
+33661 Total energy (TE) = Kinetic energy (KE) + Potential energy (PE)
KE = (1/2).m.v2, where m is mass and v is velocity
PE = m.g.h, where g is gravitational acceleration and h is height (above pool surface).
Calculate TE at diving platform (you have already calculated the KE there).
Work out the PE at the point 6metres below the platform.
Then, because TE is conserved, you can set (1/2)mv2 + PEat6metresbelowplatform= TE, where v is now the velocity at 6m below the platform. This v is the only unknown, so you can rearrange the equation to find it.
Incidentally, you should really give your results with units: Joules for energy, metres/sec for velocity.
