CPhill

"Guest's "  answer isn't unique.....for example......

117649  = 343^2

117649 =    49^3

262144  = 512^2

262144  = 64^3

I suspect that, integer-wise, this may be all

[ 6 * 6 ] ^3   = [36]^3   = 46.656  ..... too small

[ 7 * 7 ] ^3 =   [49]^3  = 117649

[8 * 8 ] ^3  =   [64]^3  = 262144

[9 * 9 ] ^3  =   [81]^3  =  531441

[ 10 * 10] ^3  = [100]^3  = 1,000,000  ...... too large

Step by Step :

1. On segment AC, construct circle with center at A and radius AC

2. And construct circle with center at C and radius AC

3. These circles will intersect at B and  D

4. And AB = BC = AC  = CD = AD  since they are equal radii

5.  Now, ABCD forms a rhombus.....and, by definition of a rhombus, its diagonals AC and BD are  perpendicular bisectors of each other.

Hope that helps !!!

I believe that the answer is   11C2  = n ( n -1) / 2   =  (11)(10)  / 2   =  55

Each point will have 10 lines connecting it to every other point, but we must divide by 2 to  prevent "double couning" since, for example, a line through point A and point E is the same as a line  through point E and point A

Dear Guest  :

I have been vaccinated against  CDD  [ Congenital Dumba$$ Disease ]   ....thus, "F'd  Up "  answers don't  trouble me as they would most. However....if you can provide proof of your alcohol consumption - empty bottles, etc.  -  to either Melody or me within 14 days, we will kindly consider your request for 25 bonus points......

Sincerely,

Sir CPhill

-12x+2=0    subtract 2 from both sides

-12x   = -2       divide both sides by  -12

x =   -2 / - 12   =    1 / 6    [ negative / negative = postiive  ]

I just gave him the 5 points for becoming a member.......I'm feeling charitable....LOL!!!!!!

Indeterminate.......to see why.......

 a / b  = c  implies that   bc  = a

Then

0 / 0   implies  that   0   times  [something]  = 0

But  "something"  could be  "anything".....thus,  0 / 0   has no fixed value........

0.0009  =  9 x 10^-4

314 visitors  x  $18  per visitor  = $ 5652

3: (g−h)(x)  = x^5 - x^3 +2 - 2sin (x)

Domain =  (- inf, + inf)