Find the number of different lines determined by 11 points, no three of which lie on the same line.
how????
+129839 I believe that the answer is 11C2 = n ( n -1) / 2 = (11)(10) / 2 = 55
Each point will have 10 lines connecting it to every other point, but we must divide by 2 to prevent "double couning" since, for example, a line through point A and point E is the same as a line through point E and point A
