AdamTaurus

Although, I would suggest at least attempting your homework, then you could use a site like that to verify your answers.

Thanks CPhill! I appreciate it.

Thanks Hectictar!

It's fine. You don't have to if you don't feel like it. I'm sure someone else on here can explain it.

Ok. Thanks a ton CPhill!

Yes! Thanks so much CPhill!

Thanks CPhill, but where did you get the x =  -20000 / [ -2 * 1000]?

Where did you get x =  -20000 / [ -2 * 1000]?

If so, then I'll rewrite it as x-0.125x=8560 just for clarity (it is easier to read like that).

\(x-0.125x=8560\)

First, I would factor an x out of the left side.

\(x(1-0.125)=8560\)

Subtract 0.125 from 1

\(x(0.875)=8560\)

Divide both sides by 0.875.

8560/0.875 = 9782.85714

\(x=9,782.85714\)

So your @ number is 9,782.85714. (If you round up at all, it won't work.)

12.5% is the same as 0.125, so is what you are asking equivalent to @-0.125@=8560?