AdamTaurus

Oh! The second 5 feet is supposed to be 15 feet.

I don't see a way to simplify it other the fact that the negatives cancel.

\(\frac{-3}{-5c}=\frac{3}{5c}\)

The best way to find this is by dividing 17 by 11.

17/11 = 1.5454545454545455

Since the answer has fractions and does not divide properly, the answer to this would be 0, but to give you a better idea of what tis means, I will demonstrate with a different problem.

Ex- How many times does 6 go into 24?

24/6=4

6 would go into 24 four times.

83.3 recurring is the same as \(83\frac{1}{3}\)

1.3 recurring is the same as \(1\frac{1}{3}\)

So your problem is equivalent to \(\frac{83\frac{1}{3}}{1\frac{1}{3}}\)

To be clearer, make them both into improper fractions.

Multiply the whole number by the denominator and add it to the numerator.

For the top, 83*3=249

Adding that to the numerator gives 250.

For the bottom, 1*3=3

Adding that to the numerator gives 4.

\(\frac{\frac{250}{3}}{\frac{4}{3}}\)

Anything divided by a fraction is the same as it multiplied by the fraction's reciprocal.

\(\frac{250}{3}*\frac{3}{4}\)

250*3=750

3*4=12

\(\frac{750}{12}\)

Simplify

\(\frac{750}{12}=\frac{375}{6}\)

That is as far as that fraction can be simplified, but it is equivalent to 62.5

\(\frac{750}{12}=\frac{375}{6}=62.5\)

Could you also possibly do the domain and range of -sqrt(2x-6).

Wow, good job Hecticar. Certainy wouldn't haven't gotten that.

Thanks!

f(x)=5x²-20

This can be applied to the formula ax²+bx+c. B just equals 0, canceling that part.

I would use max method.

Multiply a by c.

a*b=5*-20=-100

Find two factors of 100 that add to 0 and multiply to -100

In this case, it is 10 and -10

(x+10)(x-10)

That is this equations factored form. If you want me to solve for anything else, let me now.

\(d\not=0\)

\(\left(12d+13+14d^2\right)+\left(2d+1\right)\)

This is more simple than it seems.

Combine like terms.

\(14d+14+14d^2\)

Since the form is ad+b+cd², apply what it looks like to your formula.

\(a=14, b=14, c=14\)

\(\frac{3x+12}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}\)

First, you can take a 3 out of the numerator on the left.

\(\frac{3(x+4)}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}\)

Combine like factors on the top right.

\(\frac{3(x+4)}{x+4} = \frac{12x^2+8x}{2x}\)

The x+4's on the right can cancel.

\(3=\frac{12x^2+8x}{2x}\)

The left can be divided by 2x.

\(3=6x+4\)

Subtract 4 from both sides.

\(-1=6x\)

Divide both sides by 6.

\(x=-\frac{1}{6}\)