We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.

Find the exact value.


I would know how to do this if \(\frac{3\pi}{8}\) was on the unit circle.

 May 14, 2019

Well, since this is inverse sine of a sine it cancels out to return to the given angle of \(\frac{3\pi}{8}\).


But, we should always check where stuff is defined with inverse trig functions and make sure \(\frac{3\pi}{8}\) is within it. The range of \(sin^{-1}\) is \([-\frac{\pi}{2},\frac{\pi}{2}]\), and \(\frac{3\pi}{8}<\frac{\pi}{2}\), so the answer is \(\frac{3\pi}{8}\)

 May 14, 2019

12 Online Users