First one
-16x = y^2 this is a parabola opening to the left.....we have the form
4p ( x - h) = (y - k)^2
4p ( x - 0) = (y - 0)^2
The vertex is at (h, k) = (0,0)
We can find "p" [ the distance between the focus and the vertex ] as
4p = - 16 divide both sides by 4
p = - 4
The focus is given by
(0 + p, 0) = (0 + (-4), 0) = (-4, 0)
The directrix is given by
x = - (p)
x= - (-4)
x = 4
Here's a graph : https://www.desmos.com/calculator/cdaauapqz1
Second one
x^2 y^2
___ - ____ = 1
25 1
We have the form
(x - h)^2 (y -k)^2
______ - ________ = 1
a^2 b^2
This is a hyperbola intersecting the x axis with a center at (h, k) = (0, 0)
a = 5 and b = 1
Tve vertices lie along the x axis and are given by (a, 0) and (-a, 0) = (5, 0) and (-5, 0)
The foci are given by ( √[ a^2 + b^2], 0 ) and (- √[a^2 + b^2], 0 ) =
( √ [25 + 1] , 0 ) = (√26, 0) and ( - √26, 0)
The asypmtotes are given by :
y = ± (b/a) (x - h) + k =
y = ± (1/5) ( x - 0) + 0 =
y = ± (1/5)x
Here's a graph: https://www.desmos.com/calculator/aabdp29eok
Last one
x^2 y^2
___ + ____ = 1
25 16
The " + " between the terms signals an ellipse
Like the hyperbola before, this is centered at the origin = (0, 0)
The major axis is along x and the minor along y
a^2 = 25 b^2 = 16
a = 5 b = 4
The vertices here are located at ( 5, 0) , (-5, 0), (0, 4) and (0, -4)
The foci are located on the major axis and are given by ( ±√[ a^2 - b^2 ] , 0) =
( ±√[ 25 - 16 ] , 0 ) = (± √9 , 0 ) = (3, 0) and (-3, 0)
Here's a graph : https://www.desmos.com/calculator/j579zix3zu
BTW....here's a resource that I find helpful :
https://www.purplemath.com/modules/index.htm
Thank you sooo much CPhill these really helped me. One question though. For the second question, is that formula for asymptotes applicable to all hyperbolas or just this one specifically?
Whenever the hyperbola intersects the x axis [like the one we did ]
The equation of the asymptotes is
y = ± (b/a) ( x - h) + k where (h, k) is the center of the hyperbola
If the hyperbola intersects the y axis we have the form
(y - k)^2 ( x - h)^2
______ - ________ = 1
a^2 b^2
And the equation of the asymptotes is
y = ± (a/b) (x - h) + k where (h, k) is the center