+895 12.5% is the same as 0.125, so is what you are asking equivalent to @-0.125@=8560?
+895 If so, then I'll rewrite it as x-0.125x=8560 just for clarity (it is easier to read like that).
\(x-0.125x=8560\)
First, I would factor an x out of the left side.
\(x(1-0.125)=8560\)
Subtract 0.125 from 1
\(x(0.875)=8560\)
Divide both sides by 0.875.
8560/0.875 = 9782.85714
\(x=9,782.85714\)
So your @ number is 9,782.85714. (If you round up at all, it won't work.)
