CalculatorUser

Each of these quadratics have a maximum of 2 solutions as long as their discriminant works.

try creating a system of inequalities using the properties of a discriminant with a, b, c??????

Not sure if that helped I don't have much time to solve this because I have a math class in literally 5 min.

Also, what I did was trying to draw a new point (x) on AD in such that PMQX is a rectangle.

Find the total number of digits then divide by half.

do some experimenting with numbers, come on.

oh sorry I confused it with Abraham Lincoln's gettyburg speech thats why I though it was 80.

"four score and seven years ago"

factor

n^4 + 6n^3 + 11n^2 + 6n

n(n^3 + 6n^2 + 11n + 6)

n(n^2(n+6)+11(n+6))

n(n²+11)(n+6)

And i leave up to u

do some pythagorean theorem... but draw it out first.

DEM is half of DFE.

So 18 / 2 = 9.

And since G is 2/3 its way on the median.

That means GEM is 1/3 of DEM.

So.... 3????????????????????????????????????????????????????

Because G is the centroid, that is the balancing point, so according to my intuition, the triangle ABC is divided into three congruent triangles (in area) CGA, AGE, and BGC.

Does triangle DFE also have the same centroid as ABC?

If so, my intution is telling me that DFE is one-fourth of ABC.

But don't trust me, this is intuition.

The ratio of the area of PTUS to PQRS is 1:3

\(2x+2y=40\)

\(x+y=40\)

X is a shared side of PTUS and PQRS.

Since PQRS is a square, the area is x^2. Based on the ratio above, PTUS is x²/3.

Do you know why? Can you figure out the answer?

me so sorry robotics team is coming to my house  i have no time