In isosceles triangle ABC, we have AB=AC=4. The altitude from B meets overline{AC} at H. If AH=3(HC) then determine BC.
Thanks to all that answered!
Triangle ABH is a right triangle with:
Sides: a = sqrt(7), b = 3, c = 4
Area: T = 3.969
Perimeter: p = 9.646
Semiperimeter: s = 4.823
Angle ∠ A = α = 41.41° = 41°24'35″ = 0.723 rad
Angle ∠ B = β = 48.59° = 48°35'25″ = 0.848 rad
Angle ∠ C = γ = 90° = 1.571 rad
Triangle ABC is an isosceles triangle with:
a =4, b=4, Angle A =41.41 degrees.
Solving for SAS triangle we get:
Sides: a = 4, b = 4, c = 2.828
Or BC =2.828
