In isosceles triangle ABC, we have AB=AC=4. The altitude from B meets overline{AC} at H. If AH=3(HC) then determine BC.

Thanks to all that answered!

Guest Nov 23, 2019

#2**0 **

Triangle ABH is a right triangle with:

Sides: a = sqrt(7), b = 3, c = 4

Area: T = 3.969

Perimeter: p = 9.646

Semiperimeter: s = 4.823

Angle ∠ A = α = 41.41° = 41°24'35″ = 0.723 rad

Angle ∠ B = β = 48.59° = 48°35'25″ = 0.848 rad

Angle ∠ C = γ = 90° = 1.571 rad

Triangle ABC is an isosceles triangle with:

a =4, b=4, Angle A =41.41 degrees.

Solving for SAS triangle we get:

Sides: a = 4, b = 4, c = 2.828

**Or BC =2.828**

Guest Nov 24, 2019