+312 In rectangle ABCD points P and Q lie on AB and DC respectively. Angle PMQ is a right angle, M is the midpoint of BC and PB = 4/3BC. What is the ratio PM:MQ? Express your answer as a common fraction.
+19 Let's see...
The answer is 8/3.
so
and 90-
Additionally,
Therefore,
Also,
So,
Triangle PBM ~Triangle MCQ.
BC=MC*2 because M is the midpoint of line BC.
PB= (4/3)BC= (8/3)MC.
Because Triangle PBM and Triangle MCQ are similar, we can assume that PM/MQ=PB/MC=1/(8/3)=8/3.
Hope this helped! 🧭
+2862 Also, what I did was trying to draw a new point (x) on AD in such that PMQX is a rectangle.
