chilledz3non

Okay solved another one just now after class. Some of these are kind of tricky so I'll solve some of them when I'm a little more awake xD

$$\frac{a^{3}-49a}{a^{3}+7a^{2}}$$

$$=\frac{(a-7)(a^{2}+7a)}{a^{3}+7a^{2}}$$

$$=\frac{(a-7)(a^{2}+7a)}{a(a^{2}+7a)}$$ cross out the $$(a^{2}+7a)$$ from the numerator and denominator...

$$=\frac{a-7}{a}$$ and here is your final answer!

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Now time to do my Political Science homeowork xD

Okay, I solved one this morning before I went to school:

$$\frac{(b-5)^{3}}{15+7b-2b^{2}}$$

$$\frac{(b-5)(b-5)(b-5)}{(-2b-3)(b-5)}$$

Cancel like terms (the (b-5) at the top and bottom)

$$-\frac{(b-5)^{2}}{(2b-3)}$$   This is your final answer :D

I'll try and help you with a few. This thing looks like a lot of work lol .-.

I'm still kind of lost with this question :/

Since I solved the limit and it gave me two different answers for the left side and right side I chose "DNE". Could that be correct as well?

I finally found it in my textbook, but there is only one example. 

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I also did some work to prove that the limit does not exist, but I'm not sure if it is correct.

So judging from your graph Allen, I'm going to say that $$f(x)=[[x]]$$ is not continuous anywhere, since you have to lift your pencil to draw the graph. Am I right or wrong?

Thanks so much Melody :D

Woot woot!

Correct me if I'm wrong somebody. I'm not 100% sure with my answer, but this is how I solved this:

$$[(1+x)^{200}]^{\frac{1}{200}}=2000^{\frac{1}{200}$$

$$1+x =1.03873592$$

$$x=0.03873592$$

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When you plug .03873592 into the equation: (1+x)²⁰⁰ = 2000

you get the number 2000.000018 which is REALLY close to 2000. 

Again, I'm not sure of my answer so sorry guys if I'm wrong :/