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Hey guys.. My brother needs help with a couple Physics problems. I was wondering if someone could help me out?

chilledz3non  Jun 21, 2016
edited by chilledz3non  Jun 21, 2016

Best Answer 

 #3
avatar+12565 
+5

4 a   R = 16 + 12  +  (60 x 40)/(60+40) = 52 ohms

  b  V = I R  = .25 x 52 = 13 volts

  c   Voltage drop across R1 =  .25 (16) = 4

                                        R4 = .25 (12) = 3         13 - 4 - 3 = 6V across R2  (AND R3)

  d Current through R2 = V/R =  6/60 = .1 A     Power = I^2 R    or VA  =  .6 watts

ElectricPavlov  Jun 21, 2016
 #1
avatar+564 
0

I solved question #8 and got 6.3 m/s.

 

Is that right? Ill post my work later

chilledz3non  Jun 21, 2016
 #2
avatar+564 
0

Okay here is the work

chilledz3non  Jun 21, 2016
 #3
avatar+12565 
+5
Best Answer

4 a   R = 16 + 12  +  (60 x 40)/(60+40) = 52 ohms

  b  V = I R  = .25 x 52 = 13 volts

  c   Voltage drop across R1 =  .25 (16) = 4

                                        R4 = .25 (12) = 3         13 - 4 - 3 = 6V across R2  (AND R3)

  d Current through R2 = V/R =  6/60 = .1 A     Power = I^2 R    or VA  =  .6 watts

ElectricPavlov  Jun 21, 2016
 #4
avatar+12565 
+5

# 8     Using Pythagorean theorem (to find the resultant distance from the starting point)

  a^2 + b^2 = c^2

250^2 + 575^2 = c^2     c= 626.99 meter      626.99 meters/ (45 + 55)seconds = 6.27 m/s average from her starting point(as a RESULTANT)  

 

 

Her ACTUAL average speed is  (250 + 575)/(45+55) = 8.25 m/s

ElectricPavlov  Jun 21, 2016
 #5
avatar+564 
0

Thanks so much ElectricPavlov!

chilledz3non  Jun 21, 2016

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