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Hey guys.. My brother needs help with a couple Physics problems. I was wondering if someone could help me out?
4 a R = 16 + 12 + (60 x 40)/(60+40) = 52 ohms
b V = I R = .25 x 52 = 13 volts
c Voltage drop across R1 = .25 (16) = 4
R4 = .25 (12) = 3 13 - 4 - 3 = 6V across R2 (AND R3)
d Current through R2 = V/R = 6/60 = .1 A Power = I^2 R or VA = .6 watts
I solved question #8 and got 6.3 m/s.
Is that right? Ill post my work later
4 a R = 16 + 12 + (60 x 40)/(60+40) = 52 ohms
b V = I R = .25 x 52 = 13 volts
c Voltage drop across R1 = .25 (16) = 4
R4 = .25 (12) = 3 13 - 4 - 3 = 6V across R2 (AND R3)
d Current through R2 = V/R = 6/60 = .1 A Power = I^2 R or VA = .6 watts
# 8 Using Pythagorean theorem (to find the resultant distance from the starting point)
a^2 + b^2 = c^2
250^2 + 575^2 = c^2 c= 626.99 meter 626.99 meters/ (45 + 55)seconds = 6.27 m/s average from her starting point(as a RESULTANT)
Her ACTUAL average speed is (250 + 575)/(45+55) = 8.25 m/s