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Hey guys.. My brother needs help with a couple Physics problems. I was wondering if someone could help me out?

chilledz3non Jun 21, 2016

#3**+5 **

4 a R = 16 + 12 + (60 x 40)/(60+40) = 52 ohms

b V = I R = .25 x 52 = 13 volts

c Voltage drop across R1 = .25 (16) = 4

R4 = .25 (12) = 3 13 - 4 - 3 = 6V across R2 (AND R3)

d Current through R2 = V/R = 6/60 = .1 A Power = I^2 R or VA = .6 watts

ElectricPavlov Jun 21, 2016

#1**0 **

I solved question #8 and got 6.3 m/s.

Is that right? Ill post my work later

chilledz3non Jun 21, 2016

#3**+5 **

Best Answer

4 a R = 16 + 12 + (60 x 40)/(60+40) = 52 ohms

b V = I R = .25 x 52 = 13 volts

c Voltage drop across R1 = .25 (16) = 4

R4 = .25 (12) = 3 13 - 4 - 3 = 6V across R2 (AND R3)

d Current through R2 = V/R = 6/60 = .1 A Power = I^2 R or VA = .6 watts

ElectricPavlov Jun 21, 2016

#4**+5 **

# 8 Using Pythagorean theorem (to find the resultant distance from the starting point)

a^2 + b^2 = c^2

250^2 + 575^2 = c^2 c= 626.99 meter 626.99 meters/ (45 + 55)seconds = 6.27 m/s average from her starting point(as a RESULTANT)

Her ACTUAL average speed is (250 + 575)/(45+55) = 8.25 m/s

ElectricPavlov Jun 21, 2016