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Find the standard form of the eqation of a circle whose center is at (2,5) and whose radius is 4.

 May 27, 2016

Best Answer 

 #1
avatar+17747 
+10

The standard form of the equation of a circle whose center is (h, k) and whose radius is r is:

(x - h)2 + (y - k)2  =  r2

 

Since the center is (2, 5),  h = 2  and  k = 5; since the radius is 4,  r = 4:

(x - 2)2 + (y - 5)2  =  42          or          (x - 2)2 + (y - 5)2  =  16 

 May 27, 2016
 #1
avatar+17747 
+10
Best Answer

The standard form of the equation of a circle whose center is (h, k) and whose radius is r is:

(x - h)2 + (y - k)2  =  r2

 

Since the center is (2, 5),  h = 2  and  k = 5; since the radius is 4,  r = 4:

(x - 2)2 + (y - 5)2  =  42          or          (x - 2)2 + (y - 5)2  =  16 

geno3141 May 27, 2016

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