In the figure below, AB = AC = 50, AD = 52, and BC = 28. Determine CD.
"h" is the height of the triangle ABC.
h2 = (AC)2 - (BC/2)2
h2 = 502 - 142
h = sqrt(502 - 142)
h = 48
(CD+14)2 = (AD)2 - h2
(CD+14)2 = 522 - 482
(CD+14)2 = 400
CD = sqrt(400) - 14
CD = 6