In a triangle ABC, AD = 3 cm, and [ABC] = 162/3 cm2. Find the ratio of [ACD] to [BCD].
AD = 3 [ABC] = 162/3 BD = x
(√3x)(3 + x) = 2(162/3)
x = 51/3
CD = (2*162/3 ) / 81/3 = 4
[ACD] = 6 cm2
[BCD] = [ABC] - [ACD] = 102/3 cm2
[ACD] / [BCD] = 9/16
+1694 
