1. We see that the sequence is just counting by five, so the next three terms are 30, 35, 40.
We can use the \(a_1+(n+1)d\) method, where the first term is 10 and the common difference is 5. Now we get \(10+(n-1)5\), which simplifies to \(5n+5\) .
If you don't know that, we see that we are counting by 5, so we could have \(5n\) . Next, the terms are five above the normal count 5, 10, 15, etc. so we add 5 to get \(5n+5\).
2. Migo simply weights 2.7 more, or \(s+2.7\).
You are very welcome!
:P
