#1**+1 **

25_{10} + 36_{10} = 61_{10}

61 / 3 = 20(3) R 1

20 / 3 = 6(3) R 2

6 / 3 = 2(3) R 0

2 / 3 = 0(3) R 2

Read the red numbers from bottom to top :

2021_{3} = 2(3)^3 + 0(2)^2 + 2(3)^1 + 1(3)^0 = 54 + 6 + 1 = 61

CPhill Jan 5, 2019

#2**-1 **

\(25_{10}+36_{10}=61_{10}\)

Now, we see that \(3^3\) is the greatest power that fits in \(61\), and it fits twice.

\(61-3^3\times 2=7\)

Next, \(3^2\) doesn't fit, but \(3^1\) fits twice.

\(7-3^1 \times 2=1\)

Finally, \(3^0\) fits one time.

Therefore, the answer is \(2021_3\) because they fit twice, then never, then twice, then once.

CoolStuffYT Jan 5, 2019