helperid1839321

Here is what I have: 

I assigned x to be the smaller and y to be the larger

4x + 2y - 3 = 71

4x + 2y = 74 (Add 3 to both sides)

2x + y = 37 (Divide each side by 2)
 

Like CPhill said, we need some more info about the relationship between the 2 numbers to get any further.

Sorry to be rude, but can someone, please answer?

I know I made a mistake not showing you the first time, but I wanted to see if anyone else got my answer. I had 2 different answers, so I reposted this with my answer to see if it made more sense. Again, it was my fault for not posting the data I got the first time.

That was a mistake, but I wanted to see how you guys would have gotten there. Sorry again! :(

@heureka

Yes, the curve-ish passes through (2,4) and (4,2). The reason I say curve-ish is that the curve-ish part does not pass through \((2\sqrt{2}, 2\sqrt{2})\)

even though it looks like it does. That bad assumption is my own fault.

OK, that was hilarious.

Another one:

A math teacher and a textbook get kicked out of a bar. The textbook asks, "Why'd we get kicked out?" The math teacher replied, "cos(you)."

Get it?

Trigonometry is, in my opinion, kind of annoying, and is where your problem has its base.

We need to take the sine of 12° to get the ratio of height to length. sin(12) = 0.207911690818

Multiply this by 5.3: 0.207911690818*5.3 = 1.1019319613354.

The upper end of the ramp is 1.1019319613354​ meters higher than the lower end.

For left part =  (21)/(2):

Because of the laws of exponents, we can take the square root of each side of the equation, and still end up with the correct answer: \((c+1)^2=\frac{21}{2} \rightarrow c+1=\sqrt{\frac{21}{2}}\)

So \(c = \sqrt{\frac{21}{2}}+1\)

For left part = 2+(1/2):

We can still use the laws of exponents: \((c+1)^2=\frac{5}{2} \rightarrow c+1 = \sqrt{\frac{5}{2}}\)

Simplify: 

\(c=\sqrt{\frac{5}{2}}+1\)

I'm going to guess you were saying \(x^{\frac{2}{3}}\times(8x)^{\frac{1}{3}}\)

I've done some exploration of exponents on my own, and discovered a few rules I otherwise would be oblivious to. So, let's start by making the first term have a unit fraction (that is, one over something, or no fraction): \((x^{2})^{\frac{1}{3}}*(8x)^{\frac{1}{3}}\)

One of those rules is that the reciprocal power x of a number y = the xth root of y.

Another is that you can multiply bases w/ the same powers.

\(\sqrt[3]{x^2\times8x}\)

The most simple form can be found by multiplying the stuff under the same power, so:

\(\sqrt[3]{8x^3}\)

This one is even easier to simplify. 8 = 2³, so:

\(2x\)

is the answer.

Solve for a: arccos(cos(A)), cos(a)=4/8.06

arccos(4/8.06) = 60.245947106754 degrees

arccos(4/8.06) = 1.051490137995 radians

Therefore:

the measure of angle a is ~ 60.245947106754 degrees (~ 1.051490137995 radians)

I've tried to understand it so far, and I have figured out that calculus is using estimates that get closer and closer and closer to something to the point where it makes sense that something might work a certain way.

One example: \(\pi = 4(1 - \frac{1}{3} + \frac{1}{5} - \frac{1}{7} + \frac{1}{9} - \frac{1}{11} + \dots)\) Only after infinite repetitions will you get the answer.

Another example: \(\phi = 1 + \frac{1}{1+\frac{1}{1+\frac{1}{1+\dots}}}\) Again, only after infinite repetitions will you get the answer (a.k.a. the golden ratio (can be used to make a "perfect" rectangle that can be divided using a method infinite times constantly getting the same ratio), phi)