In triangle ABC, the angle bisector of < BAC meets line segment BC at D, such that AD = AB. Line segment AD is extended to E such that CD = CE and angles DBE = BAD. SHow that triagnle ACE is iscocles.
This right?
Don't you dare cheat.
This is AoPS Week... 4/5 writing problem. From the Intro to Geometry Book.
I know since I did it a few days back.
If you think that you can just come onto some site and just copy some solution, SORRY YOU ARE OUT OF LUCK.
I will personally not be allowing that. Many of your classmates on crunching on a solution and you just try to cheat.
If you need help, come back and 1)tell us what you did already, and/or 2) just ask the message board.
I get it, AoPS is hard, for me kinda too. But there's no shame in asking for help when you need it.