lokiisnotdead

if you combine like terms, \(5y+y-2y=\boxed{4y}\)

thanks!

i just have one question though, why is it equal to 17! · ( 20 · 19 · 18  -  19 · 18  -  17  -  1 )? why is there a -19*18-17-1?

yep no problem! 

ps you're so smart! these problems are really hard to figure out, and yet you do them so professionally! :)

hi guest!
 

so i haven't learned this yet (I'm only in middle school) but I'm pretty sure i got the solution.

*NOTE: THIS IS NOT MY WORK, I GOT IT FROM THE INTERNET*

i posted it on ur original question!

ok so for the first part of your question  f(x) is divisible by $x^3$, the answer is

*THIS IS ALL HEUREKA'S WORK ABOVE*

sure i'll try!

just out of curiosity where is the 2nd question from? i feel like I've seen it b4

a) there's 1 ticket out of 250, so the answer is \(\boxed{\frac{1}{250}=0.4\%=0.004}\)

b) there's 10 tickets out of 250, so the answer is \(\boxed{\frac{1}{25}=4\%=0.04}\)

c) there's 25 tickets out of 250, so the answer is \(\boxed{\frac{1}{10}=10\%=0.1}\)

ok so january is before june, right? so January can never follow after June. So, that means there is a 0% chance of that happening.