NO You are NOT fired Heureka.

Chris has CDD (he told me so)  so DO NOT pay any attention to him!!

nothing would be wrong with it if it was 435 instead of 415 :)

The 2 here are correct and the first one on the other  thread is also correct.

When you cross reference threads it might be a good idea to do it in two directions - not just one :)

So I know know that you can pull out common factors to factorise but you do not know how to do quadratics.

quadratics fall into a number of different types so lets look at the easiest ones

first I am going to expand and then simplify this

$$\\(x+2)(x-3)\\
=x(x-3)+2(x-3)\\
=x^2-3x+2x-6\\
=x^2-x-6\\$$

Now I  want to go the other direction and factorise.

$$\\x^2-x-6\\
=x^2-1x-6$$

Now I need 2 numbers that multiply to -6 and add to -1

Since they mult to give a negative number, one must be pos and one must be neg.

Since the add to a neg, the 'bigger' one must be the neg.

Must be -3 and +2         -3*2=-6         -3+2=-1      that works  :)

the answer is 

$$(x-3)(x+2)$$

------------------------------------------------------------------------------

Your turn Tenacious  

Factorise    

$$\\1) x^2+7x+6\\
2) x^2+10x+21$$

Yes I am getting too tired to think straight.

What about that extra w at the end - do you think that is a typo?

Well now you have a new toy to play with !!

Good one!    but if you are Austalian you better dial

              000

[2nd]   in the top left corner

Thanks Chris

I suppose a weird thing should have a weird name :))

75-[525-50w]

=75-525+50w

=-450+50w

or

=50w-450

$${\mathtt{21}}{!} = {\mathtt{51\,090\,942\,171\,709\,440\,000}}$$

There you go Saseflower - you are right.

To get this I used the "Calculation e.g. 1+2=3"  button from above and wrote the question in the input box.  :)