Melody

How do you even pronounce that ?   Poiuyt?

And me yesterday.

You want (to continue) the job Heureka?

The pay is lousy but you will continue to be greatly appreciated    lol     

Yes defintely at the end.

If you want the answer to 3sf and you do all your working to 3 sf there will be a build up of errors and your answer will most likely NOT be correct to 3 sf.

Yes Heureka is correct

I screwed up again.  Thanks Heureka  :))

Thanks Chris but i just plugged the numbers into the calc (incorrectly lol)

I think you have to do the derivative by hand  

i(t) = 4 sin 2t + 3t, when t = 0.6

i'(t)=4cos(2t)*2+3

i'(t)=8cos(2t)+3

i'(0.6)=8cos(2*0.6)+3

Make sue your calc is set to radians.

8*cos(2*0.6)+3=

that should give you the correct answer

$${\mathtt{8}}{\mathtt{\,\times\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\frac{{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{0.6}}{\mathtt{\,\times\,}}{\mathtt{180}}}{{\mathtt{\pi}}}}\right)}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}} = {\mathtt{5.898\: \!862\: \!035\: \!816}}$$

My entry is different from what I told you to enter because I had to enter it in degrees!

There is a post about this in the sticky topics on the bottom right of your page.

hi Saseflower,

You can check your answer but substituting 13.3 in for x on the right hand side of the question and seeig if it equals 172.

like this

-6*13.3-4(4*13.3-10)

$${\mathtt{\,-\,}}{\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{13.3}}{\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,\times\,}}\left({\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{13.3}}{\mathtt{\,-\,}}{\mathtt{10}}\right) = {\mathtt{\,-\,}}{\frac{{\mathtt{1\,263}}}{{\mathtt{5}}}} = -{\mathtt{252.6}}$$

It doesn't equal the left hand side which was 172 so  x cannot be equal to 13.3.  

Understand?  

Very nice Chris :)

$$(-1)^5\\
=-1*-1*-1*-1*-1\\
= 1 *-1*-1*-1\\
= -1 *-1*-1\\
= 1 *-1\\
= -1$$

I just love it.   I have not stopped laughing.     That's hilarious!    Thanks Chris.

I do appear to be a very jolly dinosaur.