Melody

Thanks Alan,

The answer is the x value where y=25 on Alan's graph.

if cos theta = 2/3 find tan theta 

could be  1st or 4th quad

adj = 2

hyp = 3

opp = $${\sqrt{{\mathtt{9}}{\mathtt{\,-\,}}{\mathtt{4}}}} = {\sqrt{{\mathtt{5}}}}$$

$$tan\theta=\frac{opp}{adj}=\pm \frac{\sqrt{5}}{2}$$

However, if n is not an integer we have

$$\\5*2^n=200\\\\
2^n=40\\\\
log 2^n=log 40\\\\
nlog 2=log 40\\\\
n=\frac{log 40}{log 2}\\\\$$

$${\frac{{log}_{10}\left({\mathtt{40}}\right)}{{log}_{10}\left({\mathtt{2}}\right)}} = {\mathtt{5.321\: \!928\: \!094\: \!887\: \!362}}$$

this answer is approximate.

1.03^480

$${{\mathtt{1.03}}}^{{\mathtt{480}}} = {\mathtt{1\,451\,669.855\: \!024\: \!725\: \!862\: \!255\: \!5}}$$

like

5^(1/3)

If I open the maths formual box above and insert 5^(1/3), then the output is shown below.

$${{\mathtt{5}}}^{\left({\frac{{\mathtt{1}}}{{\mathtt{3}}}}\right)}$$

I hope that helps.

Perhaps you mean the 2nd function in the top corner? 

This question does not make much sense.   

Huh?  Has this been answered somewhere else?

Anon1, you have made an error.  But it was a good try!   

Thanks 2nd anon for saying this - I have just seen CPhill's answer,

It is really time comsuming when people double post. 

And it means other people are more likely to receive no answer at all!

you use asin

This is the future value of an ordinary annuity problem.

At age 25, you set up an IRA with an APR of 5%pa.    i=0.05

you deposit $75 each month.                                    C=75

How much would there be where you retire at 65?      n=65-25=40

Please tell me how to enter this problem

Can you take it from there?