Thanks Alan.
My goodness, are you both suffering from CDD?
$$\\\frac{150}{360} \times 36\\\\ =\frac{15}{36} \times 36\\\\ =15$$
Yes you can be a kid this time if you want Rosala.
What answer did the hint give you?
you can think of positive numbers as hot numbers and negative ones as cold numbers.
if you take cold air out of a room then the room gets hotter.
so
6 - - 2 = 6 + 2 = 8
Arc cos 24/30
$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{24}}}{{\mathtt{30}}}}\right)} = {\mathtt{36.869\: \!897\: \!645\: \!844^{\circ}}}$$
I do not know if this is what you intended but it is what you asked for.
$$\\\frac{-8}{x^2}-9x-(\frac{9}{9}x^3-9x^2)\\\\ =\frac{-8}{x^2}-9x-(x^3-9x^2)\\\\ =\frac{-8}{x^2}-9x-x^3+9x^2\\\\$$
It should be + 3b
so the answer is 7b
$${\frac{{\mathtt{80}}}{{\mathtt{100}}}}{\mathtt{\,\times\,}}{\mathtt{5.95}} = {\frac{{\mathtt{119}}}{{\mathtt{25}}}} = {\mathtt{4.76}}$$
$4.76
10 X 16f^2=160f^2
Will you please stop giving us questions without the equations.