Melody

It is NOT   log base 2 times 16

It is           log base 2 of 16

$$16=2^4$$

so

$$log_2\;16=4$$

you plan to invest $16000 in 4 years when you graduate. If you earn 8.5 per year, how much will you have 14 years from now?

FV=16000(1.085)^10

$${\mathtt{16\,000}}{\mathtt{\,\times\,}}{\left({\mathtt{1.085}}\right)}^{{\mathtt{10}}} = {\mathtt{36\,175.735\: \!070\: \!678\: \!940\: \!733\: \!5}}$$

Area of base = 25*22 = 550 ft square

  $$\frac{72.4-25}{2}=\frac{47.4}{2}=23.7$$

so 2 of the triangle sides have base 22 and height 23.7 Their area combined = 2* (1/2)*22*23.7

$${\mathtt{2}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right){\mathtt{\,\times\,}}{\mathtt{22}}{\mathtt{\,\times\,}}{\mathtt{23.7}} = {\frac{{\mathtt{2\,607}}}{{\mathtt{5}}}} = {\mathtt{521.4}}$$    square feet

$$\frac{67.8-22}{2}=\frac{45.8}{2}=22.9$$

so 2 of the triangle sides have base 25 and height 22.9 Their area combined = 2* (1/2)*25*22.9

$${\mathtt{2}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right){\mathtt{\,\times\,}}{\mathtt{25}}{\mathtt{\,\times\,}}{\mathtt{22.9}} = {\frac{{\mathtt{1\,145}}}{{\mathtt{2}}}} = {\mathtt{572.5}}$$     square feet

total area =  $${\mathtt{550}}{\mathtt{\,\small\textbf+\,}}{\mathtt{521.4}}{\mathtt{\,\small\textbf+\,}}{\mathtt{572.5}} = {\mathtt{1\,643.9}}$$     square feet

If you want me to draw a picture to explain what i  have done I can do that but try and understand it by yourself first.   

side = $${{\mathtt{85\,184}}}^{\left\{{\frac{{\mathtt{1}}}{{\mathtt{3}}}}\right\}} = {\mathtt{43.999\: \!999\: \!999\: \!999\: \!99}}$$      =  44cm

diagonal of base =   $${\sqrt{{{\mathtt{44}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{44}}}^{{\mathtt{2}}}}} = {\mathtt{62.225\: \!396\: \!744\: \!416\: \!182\: \!1}}$$

diagonal of cube =  $${\sqrt{\left({{\mathtt{44}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{44}}}^{{\mathtt{2}}}\right){\mathtt{\,\small\textbf+\,}}{{\mathtt{44}}}^{{\mathtt{2}}}}} = {\mathtt{76.210\: \!235\: \!533\: \!030\: \!600\: \!9}}$$

$$\\y=(5/3)cos(4x-pi)+4\\\\
y=(5/3)cos[4(x-\frac{pi}{4})]+4$$

Phase shift is pi/4 to the right

This old post goes into more detail

$$\\\frac{3}{5}\div 7\\\\
=\frac{3}{5}\div \frac{7}{1}\\\\
=\frac{3}{5}\times \frac{1}{7}\\\\
=\frac{3}{35}$$

$$\\(a-b)(4a-2b)\\\\
=a(4a-2b)\textcolor[rgb]{1,0,0}{-b}(4a-2b)\\\\
=4a^2-2ab-4ab--2b^2\\\\
=4a^2-2ab-4ab+2b^2\\\\
=4a^2-6ab+2b^2\\\\$$

$$\\1\frac{1}{8}\times 3\frac{1}{3}\\\\
=\frac{9}{8}\times \frac{10}{3}\\\\
=\frac{\not{9}^3}{\not{8}^4}\times \frac{\not{10}^5}{\not{3}^1}\\\\
=\frac{15}{4}\\\\
=3\frac{3}{4}$$