$$\left({\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{4}}}}\right){\mathtt{\,\times\,}}{\mathtt{100}} = {\mathtt{425}}$$ cm
Yes, Heureka is the master of LaTex. His maths is not half bad either LOL
Thanks Chris and Heureka
You actually can't because there is no equal sign.
And if it did equal zero then there would be no solutions anyway because the discriminant is negative.
$$1-\sqrt2+1-\sqrt2=1+1-1\sqrt2-1\sqrt2=2-2\sqrt2$$
$${\frac{{\mathtt{66.5}}}{{\mathtt{7}}}} = {\frac{{\mathtt{19}}}{{\mathtt{2}}}} = {\mathtt{9.5}}$$ weeks
$${\mathtt{0.5}}{\mathtt{\,\times\,}}{\mathtt{2.2}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{7}}}{\mathtt{\,\times\,}}{{\mathtt{17.5}}}^{{\mathtt{2}}} = {\mathtt{3\,368\,750\,000}}$$ kg
Yes, very funny Chris :))
The question does not makes sense because the ball will not have a constant speed.
Gravity will no allow that!
Nice answer anon :))
I know nothing of physics so I am guessing but
F=mass* accel
F=112*9.8 = 1097.6 Kgm/s^2 = 1097.6 Newtons
that's what I think anyway
+118723 
