Melody

Thanks Alan :)

I have forgotten what you are proving Alan :/

$${\mathtt{\,-\,}}{\mathtt{20\,000}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{10\,000}}}{{\mathtt{1.09}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{10\,000}}}{{{\mathtt{1.09}}}^{{\mathtt{2}}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{10\,000}}}{{{\mathtt{1.09}}}^{{\mathtt{3}}}}} = {\mathtt{5\,312.946\: \!659\: \!881\: \!747\: \!821\: \!9}}$$

Thanks Dbg4thebest   

I listened to all you cips and I really enjoyed Firestone and Heroes.  

Thanks for sharing     

Thanks TR

Here is a shorter way  

$${\mathtt{500}}{\mathtt{\,\times\,}}{\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.1}}\right)}^{{\mathtt{5}}} = {\mathtt{805.255}}$$

Yes Chris, I agree, that would be a good challange  :)

I had not heard of it before james put it on the forum either .   Thanks James

Yes that is right MG, you cancel as you go.  You do not have to deal with numbers bigger than necessary that way.  

 (Oh you said so the sum, sum is addition, you meant, do the multiplication, or find the product. It is just a technicality but it is important to use the right words, especially in mathematics )

Plus it will tie in with algebra better too.  Please do it closer to my way :)

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Here is one that I will make up off the top of my head.

Do it the easiest way, with lots of cancelling.   NO Calculator, except at the end to check you answer

(use the forum calc so I can see and try to make the forum calc display it as I have done, or as near as you can).

Do you remember how to divide by a fraction?  Change it into an improper fraction first and then turn the one you are dividing by upside down (take the reciprocal of the divisor) and change the divide sign to a multiply sign.

Happy calculations   

$$\\34\frac{1}{8}\times \frac{14}{51}\div 1\frac{15}{34}$$

OH did you enjoy the popcorn.  I want some too !!!       

It sounds like you have done a lot of research DragonLance.  

That is to be commended.

I am very glad that we have helped you to do well at school too  :D  

Even so your earlier comment was rather rude.  

There is nothing to be gained by being rude to people.  :/

Thanks Chris  :)

Let me think about this

$$\\x^2+y^2=r^2\\
r=3cos\theta\\
x=rcos\theta\\
r^2=3rcos\theta\\
so\\
r^2=3x\\
so\\
x^2+y^2=3x\\
x^2-3x+1.5^2+y^2=0+2.5^2\\
(x-1.5)^2+y^2=(1.5)^2\\
$ This is a circle centre (1.5,\;0) and radius 1.5$$$

NOW I HAVE GOT IT   !!

Thanks Chris  :))