Melody

Subtract 2 from all 3

then

divide all 3 by 5

Thanks MG

Did you learn something from that ?

Standard form is the English name for scientific notation :)

Please start a new thread MG. This one is driving me n**s:)

You can reference this one from the beginning AND from the end.

Pretty Please. 

And tell me how you get on with angles. :)

Yes maybe that's what I mean :)

Yes Sir-Emo,

Welcome to the forum  

Hi Chris,

Sir Emo did it the other way around to me, that is how I used to do it too but I learned my new way from Heureka and it is better I think.

2308 base 10

you want to convert it to base 16

Just think for a moment about what the place values will be in base 16

$$16^6\quad 16^5 \quad 16^4 \quad 16^3\quad 16^2\quad 16^1\quad 16^0$$

Now all these places have numbers that are divisable by 16 - except the last one.

SO if we divide 2308 by 16 the remainder will be in the last place. The remainder is 4 so that is the last digit.

Now I divide the rest of the  number by 16.   This will effectively push all the digits over one place.

Like in base 10 if you divide 60 by 10 you get 6.... see the 6 moved to one smaller place.

2308-4=2304 and 2304 divided by 16 = 144

So now you go through the same process with 144

144/16 = has no remainder so the 2nd smallest digit is 0

144/16=9    9 is smaller than 16 so it will be the 3rd smallest digit.  

The number will be    904 base 16

The reason I like this method better is that you do not have to work out in advance how many digits your new number is going to have.  So it would be much better if you were converting really big numbers. You just keep going until the division by 16 produces a number that is less than 16.      

If it is in hex and you want to convert it to base 10 then it is

$$2308_{16}=2*16^3+3*16^2+8$$

$${\mathtt{2}}{\mathtt{\,\times\,}}{{\mathtt{16}}}^{{\mathtt{3}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{{\mathtt{16}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{8}} = {\mathtt{8\,968}}$$

$$2308_{16}=8968_{10}$$

If it is in base 10 and you want to chang it to base16

$${\mathtt{2\,308}} \,{mod}\, {\mathtt{16}} = {\mathtt{4}}$$  the last digit is 4

$${\frac{{\mathtt{2\,308}}}{{\mathtt{16}}}} = {\frac{{\mathtt{577}}}{{\mathtt{4}}}} = {\mathtt{144.25}}$$

$${\mathtt{144}} \,{mod}\, {\mathtt{16}} = {\mathtt{0}}$$    the second last digit is 0

$${\frac{{\mathtt{144}}}{{\mathtt{16}}}} = {\mathtt{9}}$$        the third last digit is 9

$$2308_{10}=904_{16}$$

check

$${\mathtt{9}}{\mathtt{\,\times\,}}{{\mathtt{16}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}} = {\mathtt{2\,308}}$$

Is 2308 in hex or is it in base 10?