Melody

what is -1.4,-3/5,9/2,1/4,0.9 in least to greatest

Ho would I go about this?

-1.4,     -3/5,     9/2,    1/4,     0.9

There is only one that is less than -1 so that one is easy.  It is the smallest one

There is only one other neg one so that is easy

Ther is only one that is MORE than 1

of the other 2, one is obviously less than a half and the other is nearly one.

So this is an easy list to sort!!

Rom, I hope that you do not mind me butting in but i could not answer your questions straight off and I wanted to think about what was happening myself.

So whether or not you are teaching the question asker, you are teaching me:)

I developed a formula for a curve that met the given criterion.

This is what I came up with.  

https://www.desmos.com/calculator/7uhpqmscci

I/You did not need to do any of this to answer the question, I was just thinking laterally. :)

The answer is very simple.

Thanks for answering Joshie17  but i think what you have said is a bit confusing.

\(-2^2 = -1*2^2 = -1*4 = -4\\ however\\ (-2)^2=-2*-2=+4\)

So it depends on what your question really is.  :))

OR do you mean

\(\sqrt[3]{520}\\ =\sqrt[3]{8*65}\\ =2\sqrt[3]{65}\)

Joshie, 

\(0.\bar{3}=\frac{1}{3}\)

BUT

1.33 is not repeating  so it is just

\(1\frac{33}{100}\)

Firstly, are you the same guest that I have been woking with here?

I am more than happy to teach you on the forum for free, I am not here to get work for myself.

Good quality private tuition would probably help you enormously, it does for many people, but it is much better if it is face to face.  

Anyway if you want to talk to me more you will need to become a member and approach me via private messaging.  :))

I am gald I can help.  Like Rom I get frustrated about answering questions when I know I am usually not teaching anything to anyone.  I would much rather put the time in on someone that I think I am actually facilitating learning for :))

Now yes, both of thos times you found the y intercept of the graph.  That is just one point but it is a start.

Now I want to go back to the questions examples that i used before.

The leading coefficient is the number in front of the highest power of x.  Whether it is positive or negative is very important in deciding the shape of the polynomial graph.

If it is positive then the graph will begin in the top right corner, that is the first quadrant.  Both x and y are positive here.

If the leading coefficient is negative the graph wil begin in the bottom right hand quadrant. Where  x is positive but y is negative.

Use Desmos to help you see what I am saying.  If you can't work it out then tell me.

https://www.desmos.com/calculator

y=3x+7

y=3x^1 +7

the y intercept is 7

the highest power(degree) is 1 so it only has one direction.   Bingo...It has to be a line!

The leading coefficient is +3 so this will beginning in the top right.  (It is a line with a positive slope!)

y=7x^2+12x+5

The y intercept is 5

the degree is 2 so it has 2 directions.   Bingo... It has to be a parabola

The leading coefficient is +7.   It starts in the top right.  It is a concave up parabola!

y=-6x^3-5x^2+12x

The y intercept is 0   (there is no constant...well there is it is an invisable 0)

The degree is 3 so it has 3 directions so it is (probably) like a sideways S

   I say probably because occassionally the directions are not clear and they look more like little kinks in the graph.  But don't worry about that.

The leading coefficient is -6  So it will begin in the bottom right.  It will look a bit like an upside down N

You should try some now:)

----------------------------

I did this post ages ago.  It is a good one and well worth understanding.  Take a look and see if you can work out what I am telling people :)

http://web2.0calc.com/questions/how-do-you-find-a-power-function-that-is-graphed

Maybe I am getting a bit carried away since you only asked about a parabola, but this is conceptual learning that I am trying to give you and if you get it it will help you enormously.  

In this post the letters, a,b,c,d, etc are just numbers :)

If you don't get it we can go back and just talk about lines and parabolas. :)

My turn to try:

f(x)=x^2+9x+18

y=0^2+9*0+18

y=0+0+18

y=18

You confused me with a new question.  LOL

YES    If   f(x)= x^2 +9x+18 then the y [really f(x) ] intercept is 18  

 SO  (0,18)  would be one point on the graph.  :))

y=x^2+9x+18 is a polynomial function

This is because the y is out the front by itself and There are a list of terms with x^(some integer) aded or subtracted together after the equal sign.

That is a VERY lay explanation but it will do for the moment.  :))

The number that is tacked on the end, the constant, will always be the y intercept!

Now the highest power of x gives the number of directions that the graph will take (sort of anyway).  This is called the degree of the polynomial.

Lets look at thes polynomial functions.

y=3x+7

y=3x^1 +7

the y intercept is 7

the highest power(degree) is 1 so it only has one direction.   Bingo...It has to be a line!

y=7x^2+12x+5

The y intercept is 5

the degree is 2 so it has 2 directions.   Bingo... It has to be a parabola

y=-6x^3-5x^2+12x

The y intercept is 0   (there is no constant...well there is it is an invisable 0)

The degree is 3 so it has 3 directions so it is (probably) like a sideways S

   I say probably because occassionally the directions are not clear and they look more like little kinks in the graph.  But don't worry about that.

Yours is y=x^2+5x+6

Tell me about its basic shape please.    :))

if n=0 then quiz:=0 else if n=1 then quiz:=1 else quiz:=quiz(n-1)+quiz(n-2) end;

This is code for the Fibonacci sequence     

y= x^2+5x+6

The y intercept is NOT around 6.

It is where x=0

Put x=0 into the equation.

y=0^2+5*0+6

y=0+0+6

y=6

The y intercept is EXACTLY 6