Melody

\(x^2 + y^2 \leq 4x + 6y+13\\ x^2-4x + y^2-6y \leq 13\\ (x^2-4x )+ (y^2-6y) \leq 13\\ (x^2-4x+4 )+ (y^2-6y+9) \leq 13+4+9\\ (x-2 )^2+ (y-3)^2 \leq (\sqrt{26})^2\\\)

Oh you can find the area yourself. Just use the formula.  :)

It was blocked because it came to the administrators attention that it was a question from a competition that is still running.

What max is telling you is that it cannot be done.

You cannot divide any number by 0 and get an answer.

You are making me reallly think here - that is a good thing.   I have a new insight.

Your logic sounds good  but I also think that your red statment is written incorrectly......

Do you mean.

 So that means NO numbers below 31 can factors of   30!+1   

Please don't just give answers itsabot.

It is possible that the asker is just being lazy ans wants to use you as a free cheat tool.

OR

They do not know how to plug the numbers in and so your answer does not help.

Better to show them how to plug in the numbers for one of the incorrect answers and then let them find the correct one on their own.

That is my suggestion :)