Thanks for answering Helpbot,
I am sorry to say that you have not solved it.
You see you have a y on both sides.
You have to have y on one side and en expression with m on the other side.
Think of m just as a constant. I mean treat it like it is a number that stays the same all the time.
\(y^2-my+(2m-1)=0\\ \text{This is a quadatic equation}\\ \text{It is of the form}\\ ay^2+by+c=0\\ \)
NOW to solve this you use the quadratic formula.
\(y = {-b \pm \sqrt{b^2-4ac} \over 2a} \)
So now you solve yours.
Hint: a=1 b=-m c=(2m-1)
Your answer will be will have an m in it.
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AFTER you have done this, think about how many answers there can be for y.
How can you make this happen?