Thanks Ginger,
Unfortunately, I really do not understand the logic behind what you have done.
I roll a die and flip three coins at the same time, and repeat this multiple times. What is the probability that I flip three heads twice in a row before I roll two 6's twice in a row?
Here is my extremely dubious attempt.
For any individual turn
P(HHH)=1/8 P(not HHH)= 7/8
P(6)=1/6 P(not 6) = 5/6
For any 2 consecutive turns
P(HHH any number, HHH not 6 (or vise versa)) = 1/8 * 1* 1/8 * 5/6 *2 = 5/192
P(6 any number of heads, 6 not all heads, (or vise versa)) = 1/6 *1 * 1/6 * 7/8 *2 = 7/144
I am only comparing these two things so the total for comparison is 5/192 + 7/144 = 43/576
Prob of favourable outcomes / prob or relevant outcome = 5/192 divided by 43/576 = 15/43
15/43 is approximately 0.3488
I doubt very much that mine is correct, Ginger seems more confident with her answer.