Melody

Please do not edit your question if it has been answered.

And even if it has not been answered yet, please explain what you are changing.

I remember this

\(log_{10}100=2\qquad because \qquad 10^2=100\)

A log is a power

so

\(if \;\;x=log_3 18\;\;then \;\;18=3^x \)

I will use change of base log law to solve this

\(log_y x = \frac{log_a x}{log_a y}\)

\(log_318=\frac{log_{10}18}{log_{10}3}\approx 2.6309\)

So it will only 'equal' 3 if it is rounded to the nearest whole number.

Thanks Grace, 

I have let admin know.

In the mean time could you please sign your name 'Grace' at the end of your posts so we know who you are.

And don't worry, you haven't done anything wrong.

I was really only upset with the asker.   

I actually do not know who answered that.  That is the problem when people post as guests.

I cannot comment because I do not know which answerer I am talking to.

No do I know which answer/s you are referring to.  

What values of x satisfy |x - 4| + |x + 4| <= 20?

x-4 is positive  when x>4

x+4 is positive when x>-4

So we have three regions to consider.

x<=-4,    x>=4    and  -4

If x <= -4 then

|x - 4| + |x + 4| <= 20

 -(x-4) +  -(x+4) <=20

-x+4 -x-4  <= 20

-2x<= 20

x>=-10

So the statement is true for   -10 <=x <= -4

You can do the other 2 regions.

Because exact answers are left for the asker.

The question has already been answered several times. 

Why have you asked this same question twice in two days you little  ##@%##$%#@@#  ?

You have 9 answers on one thread and 5 on the other.

You are totally out to waste everybody's time! 

And jugoslav, why have you fully answered on both threads without even commenting?  

Please note ianw11

Answer 1 is not correct, not all of it anyway.

I am pleased that you gave it a go though guest, and some of it is correct.