difficult geo problem - help ASAP CPhill or anyone!

Just a quick question, how did you form the equations QR = 2 (OQ * sin∠QOP) and h = sqrt[PQ2 - (QR/2)2] = 12*sqrt(3)? 

A circle is centered at O  and has an area of 48pi. Let  Q and R  be points on the circle, and let P be the circumcenter of triangle QRO. If P is contained in triangle QRO  and triangle PQR  is equilateral, then find the area of triangle PQR.

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OQ = OR = r = 4√3

∠QOR = 30º         ∠QOP = 15º           ∠QPR = 60º

QR = 2 (OQ * sin∠QOP) ==>         QR = 3.586301889 

Height of ΔPQR      h = sqrt[PQ² - (QR/2)²] = 3.105828542

[PQR] = 1/2(h * QR) = 5.569219383 u²

Please note ianw11

Answer 1 is not correct, not all of it anyway.

I am pleased that you gave it a go though guest, and some of it is correct.   

Here I wanted to correct answer #1. I copied and pasted the whole answer and have corrected what was wrong.

I apologize if I've done something wrong, teacher.

I actually do not know who answered that.  That is the problem when people post as guests.

I cannot comment because I do not know which answerer I am talking to.

No do I know which answer/s you are referring to.  

I am only on as a guest because i tried to register for an account at the end it said to check my email for account conformation or something and i did but there was nothing in my email and when i tried to log in it said invalid username or password......

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-Grace

Thanks Grace, 

I have let admin know.

In the mean time could you please sign your name 'Grace' at the end of your posts so we know who you are.

And don't worry, you haven't done anything wrong.

I was really only upset with the asker.   

Thanks Grace  :)