FIRSTLY Delphinia, do not down vote answers just becasue you think it is wrong.

If a person makes a serious attempt at answering then you should thank them and not punish them in ANY way.

I answered you before I realiszed you had done this, otherwise I probably would not have answered you.

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Suppose 5 different integers are randomly chosen from between 20 and 69, inclusive. What is the probability that they each have a different tens digit?

there are 69-20+1= 50 numbers altogether

There are 5 different 10 digits, 2,3,4,5,6

Choose a number any number prob = 1

now there are 49 numbers left and 40 of them have a tens unit not yet chose,

P of the next one being a good choice is 40/49

and so on:

\(Prob = 1 * \frac{40}{49}*\frac{30}{48}*\frac{20}{47}*\frac{10}{46}\)

You can finish it.