Melody

This page should help you 

That is what Alan said too but I always use a little supertext c to represent radians.

Here are some arrow comands that may be useful

I am sorry Daajkoma but I don't know that anyone on this forum has the knowledge to answer this question.

1 and 46 are also factors

$$3\times(5-1)\times(2\times5+1)-(5-2)^2\\

=3\times4\times(10+1)-(3)^2\\

=12\times11-9\\

=132-9\\

=123$$

-2*(-2)^2+6*(-2)-3=

$${\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\left(-{\mathtt{2}}\right)}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{6}}{\mathtt{\,\times\,}}\left(-{\mathtt{2}}\right){\mathtt{\,-\,}}{\mathtt{3}} = -{\mathtt{23}}$$

$${\mathtt{988\,346\,297\,575\,454\,298\,764\,985\,739\,875\,639\,287\,564\,949}}{\mathtt{\,\times\,}}{\mathtt{238\,479\,265\,652\,947\,259\,874\,629\,837\,469\,587\,345\,692\,387\,456\,923}} = {\mathtt{235\,700\,099\,256\,603\,630\,019\,692\,598\,651\,476\,175\,762\,623\,230\,808\,903\,859\,557\,877\,290\,077\,482\,396\,566\,367\,535\,302\,191\,927}}$$

$${{\mathtt{0.044\: \!7}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{0.325}}}} = {\mathtt{0.000\: \!050\: \!917\: \!169\: \!123\: \!3}}$$

@@ End of Day Wrap - Monday 28/4/14   Sydney, Australia Time 21:16

Hi All,

Another busy day! Lots of great answers by DavidQD, Alan, CPhill, Anonymousperson, Kitty<3, Fiyero, Creeperface2000 and Rom.  Thank you all.

I wrote a letter to Andre Massow and have received a reply - I put these together and they are posted in the forum.  Comments and suggestions are very welcome. This is the address.  I have also included it with the 'Sticky Topics'

http://web2.0calc.com/questions/communications-with-andre-massow-with-reply_1

Kitty pulled together a few replies to 'How do I put fractions into the calculator' and put the addresses into 1 post.  I thought this was good and included her reply in the Sticky Topic 'Information pages worth keeping or developing'  It is on a new last post because I cannot edit the old pages.  I presume this is because they were written in the old forum.  It really needs to be done a little more neatly.  I have suggested that Kitty does this but I don't know whether or not she will.   I'd really appreciate it Kitty!

A new member Creeperface2000 made a great post this afternoon.  Thank you.

I think that is it for this Sunday/Monday.

Thank you all,

Melody

melodymathforum@gmail.com