Melody

$$tan\theta=\frac{\sqrt3}{7}\\

\theta=tan^{-1}\frac{\sqrt3}{7}=atan\frac{\sqrt3}{7}$$

inverse tan and arc tan are the same thing.  Now just do it on the site calc.

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\frac{{\sqrt{{\mathtt{3}}}}}{{\mathtt{7}}}}\right)} = {\mathtt{13.897\: \!886\: \!248\: \!014^{\circ}}}$$

Chris told me this by message.

I believe that quadrilateral is inscribed in a circle....I think CE is the minor arc that the angle subtends....thus the angle itself = 25 degrees. I know the angle at the"bottom" of the quad has to be greater than 65 degrees and that the point "D""?? is the midpoint on that chord. After that, I'm stuck!! 

You seem to me making an awful lot of assumptions there Chris!

What does "arc m CE=50" mean?

$$x^2-4x-2^x=0$$

$$As\:\:x\rightarrow+\inf \:\:(x^2-4x-2^x)\rightarrow-\inf\\

As\:\:x\rightarrow-\inf \:\:(x^2-4x-2^x)\rightarrow+\inf$$

Therefore there must be an odd number of roots.  I'm going to look for just 1

Finding the root of this is not super easy.  It can't be factorised.

Let's consider $$f(x)x^2-4x-2^x$$

first I notice that as 

 $$If \:\: x=0 \mbox{ then } f(x)=0-0-1=-1$$

$$If \:\: x=-1 \mbox{ then } f(x)=1+4-1/2=+4.5$$

So there is at least one root between x=-1 ans x=0

Now use Newton's method of approximating roots to find it.

Thanks for answering anonymous.  We want everyone to join in.  Your answer is partly right.

There is no equal sign in the question so it is not an equation so there is nothing to solve!

you are just asked to factorise. x is the only common factor, so this is the answer.

$$2x^2-3x = x(2x-3)$$

Thanks for answering anonymous but you did make a little mistake.

To find one side  if you know the other and the area is simple;

follow this simple equation:

A = L1*L2

therefore

L2 = A / L1

The rest is good.   

It was really good to see you offer an answer gib    

You couldn't solve it anyway because there is no equal sign

But you can simplify it.   

$$0.191m^3-975.81y$$

Good attempt anonymous - It was good to see you have a go.  You did make a little mistake though.

To get the value of x

80% x = 530.36

x = 530.36 $$\div$$ 80%

x= 530.36  $$\div$$ 0.80

$${\frac{{\mathtt{530.36}}}{{\mathtt{0.8}}}} = {\mathtt{662.95}}$$

It should not have been 1.2 in the previous answer it should have been 1.25 that is why the answers are different.

Yes it is.

Hi admin,

I am sorry but I don't understand your answer.