How do you factor 2x^2-3x

Thanks for answering anonymous.  We want everyone to join in.  Your answer is partly right.

There is no equal sign in the question so it is not an equation so there is nothing to solve!

you are just asked to factorise. x is the only common factor, so this is the answer.

$$2x^2-3x = x(2x-3)$$

=>    x(2x-3)=0 or (x-0)(2x-3)=0

=>  then x=0, 2x=3

=>          x=0,  x=3/2