Yes that is much better zegroes,
If you use the math(input=result) button you get
$${\frac{{\mathtt{1}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{9}}} = {\mathtt{200\,000\,000}}$$
Actually I think your answer is probably better!
That's ok zegroes,
There is also the Math(Input=result ) button on the answer page. So if you do want do do a calculator answer you can type it in there and the asker can at least see what you have answered. Even that is better than giving just the answer.
But ususally other answers are better anyway.
$$\begin{array}{rll} (x+2)(x-2)&=&x(x-2)+2(x-2)\\ &=&x^2-2x+2x-4\\ &=&x^2-4 \end{array}$$
You really need to learn to recognise this as a difference of squares.
The brackets are the same except one has a - and the other has a +
$$\boxed{(x+a)(x-a)=x^2-a^2}$$
This is a great piece of writing.
I love all those analogies. I'll ponder them for ages. Thank you Mr know-it-all
I don't get it reinout-g. Am I just too old? How sad.
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12-(8-2)=12-6=6
Okay, thanks Heureka,
I think that I have got it.
\begin{array}{rll} 2x-8&=&6-5x\\ 7x&=&14\\ x&=&2 \end{array}
$$\begin{array}{rll} 2x-8&=&6-5x\\ 7x&=&14\\ x&=&2 \end{array}$$
hi Heureka,
I have only done this type of setting out with equarray.
but i haven't been able to get equarray to work on this forum.
Thankyou for showing me how I can do it with array.
I don't quite understand what {rll}stands for.
Can you explain please?
I think I will try equarray again and see if I can get it to work. I tried again - it still doesn't work.
+118725 
