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# 5=11+2(x-1)

0
397
5

5=11+2(x-1)

Guest May 21, 2014

#4
+19076
+5

hi Melody,

{rll...} is the alignment.

1. Field r (right-alignment) bevor first "&"

2. Field l (left-alignment) after first "&"

3. Field l (left-alignment) after second "&"

and so on...

r = right alignment

c = center alignment

l = left alignment

heureka

heureka  May 21, 2014
Sort:

#1
+91928
+5

$$5=11+2(x-1)\\ 5-11=11+2(x-1)-11\\ -6=2x-2\\ -6+2=2x-2+2\\ -4=2x\\ -4/2=x\\ x=-2$$

Melody  May 21, 2014
#2
+19076
+5

5=11+2(x-1)    x?

$$\begin{array}{rll} 5&=&11+2(x-1)\quad | \quad -11\\ 5-11&=& 2(x-1)\\ -6&=& 2(x-1)\quad | \quad :2\\ -\frac{6}{2}&=& (x-1)\\ -3&=& x-1\quad | \quad +1\\ -3+1&=& x\\ -2&=& x\\ \end{array} \\ \boxed{x=-2}\\$$

Latex Code:

\begin{array}{rll}
5-11&=& 2(x-1)\\
-\frac{6}{2}&=& (x-1)\\
-3+1&=& x\\
-2&=& x\\
\end{array} \\
\boxed{x=-2}\\

Proof:

$$\begin{array}{rll} 5&=&11+2*({-2}-1)\\ 5&=&11+2*(-3)\\ 5&=&11-2*3\\ 5&=&11-6\\ 5&=&5\\ \end{array} \\$$

Latex code:

\begin{array}{rll}
5&=&11+2*(\textcolor[rgb]{1,0,0}{-2}-1)\\
5&=&11+2*(-3)\\
5&=&11-2*3\\
5&=&11-6\\
5&=&5\\
\end{array} \\

heureka  May 21, 2014
#3
+91928
0

hi Heureka,

I have only done this type of setting out with equarray.

but i haven't been able to get equarray to work on this forum.

Thankyou for showing me how I can do it with array.

I don't quite understand what {rll}stands for.

I think I will try equarray again and see if I can get it to work. I tried again - it still doesn't work.

Melody  May 21, 2014
#4
+19076
+5

hi Melody,

{rll...} is the alignment.

1. Field r (right-alignment) bevor first "&"

2. Field l (left-alignment) after first "&"

3. Field l (left-alignment) after second "&"

and so on...

r = right alignment

c = center alignment

l = left alignment

heureka

heureka  May 21, 2014
#5
+91928
0

Okay, thanks Heureka,

I think that I have got it.

Melody  May 21, 2014

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