Melody

I gave you another 3 points.

Thank you for your excellent answer NinjaDivo 

I have included the address of this  answer in the Sticky note: "Information pages worth keeping or developing"

It was CPhill's suggestion but I thought it was a god idea too!

It is a good idea to think about a number line when you deal with negative and positive numbers.

What is the biggest number 14 is, it is furthest over towards the right.

(14 is really +14 the positive sign is just invisable but it really is there!)

Any number to the left of 14 is smaller than 14

So, ALL the negative numbers are smaller than aLL the positive numbers!

Well, put them on the forum and we will see.  

10 to the power of 16 is 1 followed by 16 zeros.  You do not need a calculator for powers of 10.  They are easy!

10^7 = 1 with 7 zeros = 10 000 000

etc     

Tealftlove, you are obviously capable of inserting pictures - Your instructions keep giving us a different question from the one you seem to want answered.  It is very confusing.  

I walk around in a fog of confusion ALL THE TIME.  I do not need you to make the fog more dense!! lol

This is number 10

This is me!

Thank you CPhill and Problem,

First the queston in the heading is different from the question in the body of the post so CPHill and Problem have answered different questions.

ANONYMOUS - Please be much more careful next time you make a post.

CPhill's answer is much better because Problem's answer is an estimate.  It is not an exact value for the question.

ALSO,

The second solution that Problem has given is wrong. 

$$\sqrt{3}-\frac{4}{1+\sqrt{3}}\\\\
=\frac{\sqrt{3}(1+\sqrt{3})}{1+\sqrt{3}}-\frac{4}{1+\sqrt{3}}\\\\
=\frac{\sqrt{3}+3-4}{1+\sqrt{3}}\\\\
=\frac{\sqrt{3}-1}{1+\sqrt{3}}\\\\
=\frac{\sqrt{3}-1}{1+\sqrt{3}}\times\frac{1-\sqrt{3}}{1-\sqrt{3}}\\\\
=\frac{-(\sqrt{3}-1)^2}{1-3}\\\\
=\frac{-(3-2\sqrt{3}+1)}{-2}\\\\
=\frac{-(4-2\sqrt{3})}{-2}\\\\
=2-\sqrt{3}\\\\$$

ACTUALLY

1) If the square root is written into the question then, by convention, the answer is POSITIVE.

$$\sqrt{4}=+2$$

2) However, if the question is

$$x^2=4$$

then this is how you solve it

$$\sqrt{x^2}=\pm\sqrt{4}\\

x=\:\pm\; 2$$

This is because the square root was not a part of the question.  It was introduced as a part of the solution.

So this time there are 2 answers, +2 and -2

The question is jibberish hence there is no mathematical answer.

BUT WAIT, what is that i hear.

THE ANSWER IS ....... 42

Oh Sorry Lord from far future time.  I have erred. Please leave me with my head.  

One headless moderator is more than any forum doth need.

Your humble servant.

Lady Guinevere.

It's when you are reduced to threats and witchcraft that I KNOW I am in the lead!!!!!